Solution to 2008 Problem 62

Gauss's Law states that
\begin{align*}\int_{\text{surface}} \mathbf{E} \cdot d \mathbf{A} = \frac{Q_{\text{enclosed}}}{\epsilon_0}\end{align*}
We are told that Q_{\text{enclosed}} = 1 \cdot 10^{-9} \mbox {C}, so the total flux through the surface is
\begin{align*}\frac{Q_{\text{enclosed}}}{\epsilon_0} &= \frac{1 \cdot 10^{-9} \mbox { C}}{8.85 \cdot 10^{-12} \;\mathrm{C...
So, the flux through the rest of the surface is approximately \boxed{200 \;\mathrm{N}\;\mathrm{m}^2\mathrm{/}\mathrm{C}}. Therefore, answer (E) is correct.

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