Solution to 2008 Problem 47

If \lambda is the length of the pipe, then the fundamental frequency corresponds to
\begin{align*}\frac{\lambda}{4} = L\end{align*}
The next lower wavelength will correspond to
\begin{align*}\frac{3\lambda}{4} = L\end{align*}
The wavelength is divided by 3, so the frequency is multiplied by 3, so the next higher frequency is
\begin{align*}\left(131 \mbox{ Hz}\right) \cdot 3 = \boxed{393 \mbox{ Hz}}\end{align*}
Therefore, answer (D) is correct.

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