Solution to 2008 Problem 42

The horizontal distance between the a crest and an adjacent trough of either waveform is approximately 3 \mbox{ cm}. If the waveform in channel 1 is shifter approximately 2 \mbox{ cm}, then it will align with the waveform in channel 2. So, the phase difference between the two waveforms is approximately
\begin{align*}2 \mbox{ cm} \cdot \frac{180^{\circ}}{3 \mbox{ cm}} = \boxed{120^{\circ}}\end{align*}
Therefore, answer (E) is correct.

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