Solution to 2008 Problem 41

The energy of a photon with frequency \nu is h \nu, where h = 2 \pi \hbar is Planck's constant. Assuming all of this energy is transferred to a single a electron, the electron will have energy h \nu - \phi after being ejected from the metal. The potential difference required to decelerate such an electron until it stops is V = (h \nu - \phi)/e. So, the slope of the line is \boxed{h/e}. Therefore, answer (B) is correct.

return to the 2008 problem list

return to homepage

Please send questions or comments to where X = physgre.