Solution to 2008 Problem 4

The magnetic field generated by the wire will be azimuthal with its direction determined by the right hand rule. From the Lorentz force law,

\begin{align*}\mathbf{F} = q \mathbf{v} \times \mathbf{B}\end{align*}
it follows that there will be no magnetic force on the loop because \mathbf{v} and \mathbf{B} are parallel. Therefore, answer (E) is correct.

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