We use Faraday's Law in integral form
We choose to traverse the loop in a clockwise direction. We also choose the reference direction of the current to be in the counter-clockwise direction. Then, where is the voltage difference between the upper left-hand corner of the circuit and the lower left-hand corner of the circuit and is the charge on the upper plate of the capacitor. Also, So, Faraday's Law is At , and , so the solution to this equation is and The energy stored in the inductor as a function of time is therefore Thus, answer (A) is correct. |

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