We use Faraday's Law in integral form
We choose to traverse the loop in a clockwise direction. We also choose the reference direction of the current to be in the counter-clockwise direction. Then,
where is the voltage difference between the upper left-hand corner of the circuit and the lower left-hand corner of the circuit and is the charge on the upper plate of the capacitor. Also,
So, Faraday's Law is
At , and , so the solution to this equation is
The energy stored in the inductor as a function of time is therefore
Thus, answer (A) is correct.