Solution to 2008 Problem 22

The rest energy of the electron is m_e c^2. So, the total energy is E = 4 m_e c^2. Therefore,
\begin{align*}E^2 = p^2 c^2 + m_e^2 c^4\end{align*}
can be solved for p:
\begin{align*}p = \boxed{m_e c\sqrt{15}}\end{align*}
Therefore, answer (C) is correct.

return to the 2008 problem list

return to homepage

Please send questions or comments to where X = physgre.