Solution to 2008 Problem 17

By symmetry the electric field will be radial. So, if we apply Gauss's Law to a cylinder with radius r and length d whose axis is along the wire, we obtain

\begin{align*}E \cdot 2 \pi r d = \frac{Q_{\text{enclosed}}}{\epsilon_0} = \frac{\lambda d}{\epsilon_0} \Longrightarrow E = \...
Therefore, answer (A) is correct.

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