Solution to 2001 Problem 63

Recall the Wien displacement law, which states that
\begin{align*}\lambda_{\text{max}} \cdot T = 2.9 \cdot 10^{-3} \mbox{ m K}\end{align*}
where \lambda_{\text{max}} is the wavelength emitted by a blackbody at temperature T at which the intensity is a maximum. From this, we can easily find the temperature given the \lambda_{\text{max}} \approx 2 \;\mu\mathrm{m} from the graph:
\begin{align*}T = \frac{2.9 \cdot 10^{-3} \mbox{ m K}}{\lambda_{\text{max}}} = \frac{2.9 \cdot 10^{-3} \mbox{ m K}}{2 \;\mu\m...
Therefore, answer (D) is correct.

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