Solution to 2001 Problem 54

The definition of impulse is
\begin{align*}\mathbf{J} := \int_{t_1}^{t_2} \mathbf{F} dt\end{align*}
So, the impulse is the area under the curve. The area of each triangle is 1 \mbox{ N s}, so the total impulse delivered to the particle is \boxed{2 \mbox{ N s}}. Therefore, answer (C) is correct.

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