Solution to 2001 Problem 50

The relationship between the resonant frequency of a pipe, the resonant wavelength of the pipe, and the speed of sound in air is
\begin{align*}\lambda f = v\end{align*}
where \lambda is fixed by the length of the pipe. We are told that v is decreased by 3 \%; therefore, the new frequency is
\begin{align*}\frac{440 \mbox{Hz} \cdot 0.97 v}{v} = 426.8 \mbox{ Hz}\end{align*}
Therefore, answer (B) is correct.

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