Solution to 2001 Problem 32

Recall the equation
\begin{align*}E^2 = m^2 c^4 + p^2 c^2\end{align*}
where E is the total energy of a particle, m is the rest mass of the particle, c is the speed of light, and p is the particle's relativistic momentum. We are given that E = 2 mc^2, therefore, this equation becomes
\begin{align*}4 m^2 c^4 = m^2 c^4 + p^2 c^2 \Rightarrow p = \boxed{mc \sqrt{3}}\end{align*}
Therefore, answer (D) is correct.

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