Solution to 2001 Problem 25

We apply the parallel axis theorem, using the fact that the moment of inertia of a rod (with mass m and radius r) about an axis through the center of mass and perpendicular to the plane of the rod is (1/2) m r^2. The moment of inertia of the system is:
\begin{align*}7 \cdot (1/2) m r^2 + 6 \cdot m \left(2r \right)^2 = m r^2 \left(7/2 +24 \right) = \boxed{m r^2 \left(55/2 \rig...
Therefore, answer (E) is correct.

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