This is an example of nonuniform circular motion.
The component of the particle's acceleration in the tangential direction is given by where is the particle's velocity. The component of the particle's acceleration in the radial direction is We are given that and . Therefore, We are also given that , therefore, So, the tangential and the radial component of the particle's acceleration have the same magnitude. Therefore, the resultant acceleration vector makes a angle with each of them. The particle's velocity vector also points in the tangential direction, therefore, the resultant acceleration vector makes a angle with it also. Therefore, answer (C) is correct. |

Please send questions or comments to X@gmail.com where X = physgre.