Solution to 1996 Problem 67

The formula for the Schwarzschild radius is
\begin{align*}r_S = \frac{2 G M}{ c^2}\end{align*}
where G is the universal gravitational constant, c is the speed of light, and M is the mass of the black hole. Plugging in M = 5.98 \cdot 10^{24} \mbox{ kg} gives
\begin{align*}r_s = \frac{2 \cdot 6.67 \cdot 10^{-11} \;\mathrm{m}^2\mathrm{/}\mathrm{(}\mathrm{kg}\;\mathrm{s}^2\mathrm{)} \...
Therefore, the correct answer is (C), 1 \mbox{ cm}.

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