Solution to 1996 Problem 59

The energy of a photon with wavelength \lambda is
\begin{align*}E = h c / \lambda\end{align*}
where c is the speed of light and h is Planck's constant. If we assume the energy released in the femtosecond pulse is equal to the peak power multiplied by one femtosecond, then the number of photons released is
\begin{align*}\frac{10 \cdot 10^3 \mbox{ W} \cdot 10^{-15} \mbox{ s}}{h c/\lambda} = \frac{10 \cdot 10^3 \mbox{ W} \cdot 10^{...
Therefore, answer (B) is the correct answer.

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