We use the integral form of Faraday's Law,
If we take the path to be the circular wire loop (and we neglect the fact that it appears not to be a complete circle in the figure), then the left-hand side of the equation above is equal to the induced emf. where is the angle between the normal to the circular loop and the magnetic field. The wire loop rotates with an angular speed of , therefore, where is a constant. So, This equation can only hold if It follows then that Therefore, answer (C) is correct. |

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