Solution to 1992 Problem 80

The minimum wavelength corresponds to the case when the electron transfers all of its energy to a photon. The electron has 25 \text{ keV} of energy. The wavelength of a photon is related to its energy by E = 2 \pi \hbar c/\lambda. Therefore, the minimum wavelength is

\begin{align*}\lambda_{min} &= \frac{2 \pi \hbar c}{25 \text{ keV}} \\&\approx \frac{2 \pi \cdot 200 \text{ MeV fm}}{...
Therefore, answer (B) is correct.

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