Solution to 1992 Problem 64

Recall Maxwell's equations:
\begin{align*}\nabla \cdot \mathbf{E} &= \frac{1}{\epsilon_0}\rho \\\nabla \times \mathbf{E} &= -\frac{\partial \math...
If you plug the given electric field into Gauss's Law, you will find that
\begin{align*}k = \frac{1}{\epsilon_0}\rho\end{align*}
We are told that k is a nonzero constant. Therefore, \rho must also be nonzero, and so there must be charge density in the region. Therefore, answer (B) is correct.

return to the 1992 problem list

return to homepage

Please send questions or comments to where X = physgre.