Solution to 1986 Problem 9

The relevant formula is

\begin{align*}I = A \cdot v_d \cdot q \cdot n\end{align*}
where A is the cross-sectional area of the wire, v_d is the drift velocity of the charge carriers, q is the charge of the charge carriers, and n is the number density of the charger carriers. Thus,
\begin{align*}v_d = \frac{I}{A \cdot q \cdot n} = \frac{100 \mbox{ A}}{\pi \cdot \left(0.01 \mbox{ m/s}\right)^2 \cdot \left(...
Hence, answer (D) is correct.

return to the 1986 problem list

return to homepage

Please send questions or comments to where X = physgre.