Solution to 1986 Problem 60

The force associated with this potential is
\begin{align*}F = - 2 b x\end{align*}
So, the spring constant is k = 2 b and the angular frequency of the oscillations is:
\begin{align*}\omega = \sqrt{\frac{2b}{m}}\end{align*}
This depends only on b and m, hence answer (C) is correct.

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